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new idea on cider
Well, here is a new idea on cider, Your comments please! How would it be to use store bought apple juice, Put the correct amount of everclear or grain alcohol to make a ABV of about 5 to 8 percent, keg it and carbonate it artificially. Man, it would sure taste like apple and be just like apple juice, which i am crazy about. Anyone here ever thought about doing this?
Thanks
Aaron
Thanks Ferminator, I have seen sparkling apple juice, but it was kinda expensive, so i decided to try to make it in bulk to make it less expensive. Dont know how it would work doing it the way i suggested, but i am going to try it and see. Now all i need is a chemist or mathematician to figure the amount of alcohol to make it 6 to 8 percent ABV using 2 and one half gals apple juice and 100 proof grain alcohol. Your posts have been a great help throughout the year.
Wesley
It just can't be as good.
If you ferment the cider you get phenols, esters, and lots of other complex stuff I can't think of now. I think it would be like beer with no hops. Something that makes it very interesting to the pallet and nose would be missing.
I have had some very highly rated commercial ciders and I was not impressed. They where very much like nice pasteurized apple juice with a little grain alcohol added. It sure seems like that is what a lot of people expect it to be but I think they are wrong. Good cider should be like a fine wine. Much more complex.
Ethan
wesley wrote:
Thanks Ferminator, I have seen sparkling apple juice, but it was kinda expensive, so i decided to try to make it in bulk to make it less expensive. Dont know how it would work doing it the way i suggested, but i am going to try it and see. Now all i need is a chemist or mathematician to figure the amount of alcohol to make it 6 to 8 percent ABV using 2 and one half gals apple juice and 100 proof grain alcohol. Your posts have been a great help throughout the year.
Wesley
To make 6% ABV you would need 43.648 ounces of 100 proof, and to make 8% ABV you'd need 45.7 ounces. The formula this was derived from follows:
A*a + B*b = (A+B)*d where A and B are volumes of drink, and a,b and d are the percent solution of a given material, in this case ethanol.
In the general case of a given A, a, b and d we obtain:
A*a + B*b = (A+B)*d --> A*a + B*b = A*d +B*d --> B(b-d) = A(d-a) --> B = ((A(d-a))/(b-d))
In this case we have A = 2.5, a=0, b=.5 and d=.06 or .08. So we then get for some d:
2.5*0 + B*.5 = (2.5+B)*d --> (.5-d)B = 2.5*d --> B = ((2.5*d)/(.5-d))
Thus d=.06 yields B = ((2.5*.06)/(.44)) = .341 gallons and d=.08 yields B = ((2.5*.08)/(.42)) = .357 gallons.
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